C Code 33 _ find the sum of STABLE and UNSTABLE elements in the array and show their difference

C Code 33 _ find the sum of STABLE and UNSTABLE elements in the array and show their difference

Problem:

Given a array of integers and their size,
find the sum of STABLE and UNSTABLE elements in the array and
show their difference.

Sample Input:

5
11 50 112 22 111

Sample Output:  

stable=11 50 22 111
unstable=112
difference=82

Explanation:

STABLE-numbers with equal number of each digit-a number in which frequency of digits are equal.
example:-
112233 is a stable number since,
        1 occurs twice , 2 occurs twice so does 3
        i.e all digits in a given number must have equal frequencies
        Similarly,
123 (1,2,3 each occur once)
355533 (3,5 each occur thrice)
are STABLE NUMBERS.
**************************************************
8892 is not a stable number(UNSTABLE),(8's frequency 2, 9 & 2 frequency 1)
Similarly,
2122(2 occurs thrice,1 only once)
5667(6 occurs twice where as 5 & 7 occur only once)
are UNSTABLE NUMBERS.

Program:

#include<stdio.h>

bool isStable(int n)

{

int freq[10],Freqf[10];

//freq-to find the frequency of each digit

for(int i=0;i<10;i++)

freq[i]=Freqf[i]=0;

while(n!=0)

{

freq[n%10]++;

n/=10;

}

for(int i=0;i<10;i++)

{  

if(freq[i]==0)

continue;

Freqf[freq[i]]++;

//Freqf-to find the frequency of frequency

}

for(int i=0;i<10;i++)

{

if(Freqf[i]>0)

n++;

if(n>1)

return 0;    

}

return 1;

}

int main()

{

int size,inp[15],diff=0,stable[15],unstable[15],i,k,j;

scanf("%d",&size);

for(i=k=j=0;i<size;i++)

{

scanf("%d",&inp[i]);

if(isStable(inp[i]))

{

diff+=inp[i];

stable[k++]=inp[i];

}

else

{

diff-=inp[i];

    unstable[j++]=inp[i];

    }

}

printf("\nstable=");

for(i=0;i<k;i++)

printf("%d ",stable[i]);

printf("\nunstable=");

for(i=0;i<j;i++)

printf("%d ",unstable[i]);

printf("\ndifference=%d",diff);

}

Output:

Thank You ...

* * * * * * * The above Program is contributed by AjayRam KV * * * * * * * *