C Code 23 _ To Find Whether any pair of elements in the given array yields the given sum(Google Interview Question)
Sample Input:
5 //# of elements in array
1 2 3 4 5 //array elements
9 //sum
Sample Output:
4 and 5 yields a sum of 9
Program:
#include<stdio.h>
int main()
{
int
a[50],n,i,sum,j,f=0;
printf("Enter
# of elements : ");
scanf("%d",&n);
printf("\n\nEnter
%d elements : ",n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
printf("\n\nEnter
the sum to find whether any corresponding pair yielding that sum is available
in the array : ");
scanf("%d",&sum);
for(i=0;i<n-1;i++)
{
for(j=i;j<n;j++)
{
if((a[i]+a[j])==sum)
{
printf("\n\n%d
and %d yields the sum of %d",a[i],a[j],sum);
f=1;
}
}
}
if(f==0)
{
printf("\n\nNo
pair in the array yiels the given sum");
}
return
0;
}
Output:
Thank You ...
0 comments: