C Code 28 _ Convert a Base 17 number to a Decimal number[TCS NQT Programming Question]

C Code 28 _ Convert a Base 17 number to a Decimal number[TCS NQT Programming Question]

Given a maximum of 4 digit to the base 17,(A -> 10 , B -> 11 , C -> 12 , D -> 13 , E -> 14 , F ->15 , G -> 16 ) as Input , output is a decimal value.

Example : 

input  : 1A

output : 27

solving: A means 10 , so (10 * 17 ^ 0) + (1 * 17 ^ 1) = 27

simillarly,

 input : 1B2 

output : 478

Solving : B means 11 , so  (2 * 17 ^ 0) + (11 * 17 ^ 1) + (1 * 17 ^ 2) = 478 

Program:

#include<stdio.h>

#include<string.h>

#include<math.h>

int main()

{

                char a[20];

                int i,n,l,j=0,sum=0;

                printf("\nEnter the Input : ");

                scanf("%s",a);

                l=strlen(a);

                for(i=l-1;i>=0;i--)

                {

                                if(a[i]>=65&&a[i]<=90)

                                {

                                                n=a[i]-65+10;

                                }

                                if(a[i]>=48&&a[i]<=57)

                                {

                                                n=a[i]-48;           

                                }

                                sum=sum+n*pow(17,j);

                                j++;       

                }

                printf("\n\nThe Output is : %d",sum);

                return 0;

}

Output:

Thank You ...